SOLUTION: Ricky is filling a 8 inch by 4 inch by 4 1/2 inch rectangular box with cubic blocks. The blocks come in 2 different sizes 1 cubic inch and 1/8 of a cubic inch. What is the least am

Algebra ->  Sequences-and-series -> SOLUTION: Ricky is filling a 8 inch by 4 inch by 4 1/2 inch rectangular box with cubic blocks. The blocks come in 2 different sizes 1 cubic inch and 1/8 of a cubic inch. What is the least am      Log On


   

Question 864785: Ricky is filling a 8 inch by 4 inch by 4 1/2 inch rectangular box with cubic blocks. The blocks come in 2 different sizes 1 cubic inch and 1/8 of a cubic inch. What is the least amount of the smaller blocks that Ricky will need to use?
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
8*4*4=128 cubic inch blocks
8*4*4.5=144
144-124=16
16*8=128 1/8 in^3