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| Question 864674:  For the hyperbola represented by  [(y+2)^2]/4 - [x^2]/12=1  find the foci and vertices
 Answer by lwsshak3(11628)
      (Show Source): 
You can put this solution on YOUR website! For the hyperbola represented by [(y+2)^2]/4 - [x^2]/12=1 find the foci and vertices 
  Given hyperbola has a vertical transverse axis.
 Its standard form of equation:
  , (h,k)=coordinates of center for given hyperbola:
 center: (0,-2)
 a^2=4
 a=2
 vertices: (0,-2±a)=(0,-2±2)=(0,-4) and (0,0)
 b^2=12
 c^2=a^2+b^2=4+12=16
 c=√16=4
 foci:  (0,-2±c)=(0,-2±4)=(0,-6) and (0,2)
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