SOLUTION: find three consecutive odd integers such that twice the sum of the first two 11 is more than three times the greatest
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Question 864577
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find three consecutive odd integers such that twice the sum of the first two 11 is more than three times the greatest
Answer by
CubeyThePenguin(3113)
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consecutive odd integers: (x-2), x, (x+2)
2((x-2) + x) = 11 + 3(x+2)
2(2x-2) = 3x + 17
4x - 4 = 3x + 17
x = 21
The integers are 19, 21, and 23.