SOLUTION: part of the proceeds from a garage sale was $610 worth of $10 and $20 bills.if there are 7 more $10 bills than $20 bills, how many $10 and $20 bills were there each?

Algebra ->  Customizable Word Problem Solvers  -> Finance -> SOLUTION: part of the proceeds from a garage sale was $610 worth of $10 and $20 bills.if there are 7 more $10 bills than $20 bills, how many $10 and $20 bills were there each?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 864539: part of the proceeds from a garage sale was $610 worth of $10 and $20 bills.if there are 7 more $10 bills than $20 bills, how many $10 and $20 bills were there each?
Answer by checkley79(3341) About Me  (Show Source):
You can put this solution on YOUR website!
LET X BE THE NUMBER OF $20 BILLS
LET X+7 BE THE NUMBER OF $10 BILLS.
20X+10(X+7)=610
20X+10X+70=310
30X=310-70
30X=240
X=240/30
X=8 $20 BILLS.
8+7=15 $ 10 BILLS.
PROOFS:
20*8+15*10=310
160+150=310
310=310