SOLUTION: Portland and Seattle are about 180 miles apart. The da Vinci family leaves Seattle at the same time as the Fermat family leaves Portland. The Da Vinci family travels at a constant
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Question 864405: Portland and Seattle are about 180 miles apart. The da Vinci family leaves Seattle at the same time as the Fermat family leaves Portland. The Da Vinci family travels at a constant speed of 55 mph to Portland, and the Fermat family travels to Seattle at a constant speed of 65 miles per hour.
When and where ( how many miles from Seattle or Portland) will the two families meet and pass on the road. Assume that neither family stops and the speed is constant. Use a table or a graph and an equation to model this situation. Explain how u solved the problem.
I need to know how to start these word problems :( Answer by josgarithmetic(39615) (Show Source):
The question asks about time and distance or position between Portland and Seattle when the two families are at the same place. The "when" is the time quantity, t. Use RT=D relationship for uniform rates for motion to get an expression for distance traveled for each family.
The key equation to obtain from examining this data is the sum of the distances being 180 miles. hours. This is .
WHERE MEET?
DaVinci family left from Seattle, going to Portland. They will be miles from Seattle heading toward Portland when they are at the same position as the Fermat family.
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