SOLUTION: I need help with this question: use Descartes's Rule of Signs to determine the possible number of positive and negative zeros of the function: f(x)=x^6+4x^5-4x^4+5x^3-5x^2+x-5
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-> SOLUTION: I need help with this question: use Descartes's Rule of Signs to determine the possible number of positive and negative zeros of the function: f(x)=x^6+4x^5-4x^4+5x^3-5x^2+x-5
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Question 86422: I need help with this question: use Descartes's Rule of Signs to determine the possible number of positive and negative zeros of the function: f(x)=x^6+4x^5-4x^4+5x^3-5x^2+x-5 Answer by Nate(3500) (Show Source):
You can put this solution on YOUR website! f(x) = x^6 + 4x^5 - 4x^4 + 5x^3 - 5x^2 + x - 5
f(+x) ~> (+) (+) (-) (+) (-) (+) (-)
Positive Roots: 5
f(-x) ~> (+) (-) (-) (-) (-) (-) (-)
Negative Roots: 1
~~~
Pos: 5 . 3 . 1
Neg: 1 . 1 . 1
Img: 0 . 2 . 4
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