Question 864196: How many ounces of a 20% alcohol solution and a 44% alcohol solution must be combined to obtain 51 ounces of a 28% solution? Answer by checkley79(3341) (Show Source):
You can put this solution on YOUR website! .20x+.44(51-x)=.28*51
.20x+22.44-.44x=14.28
-.24x=14.28-22.44
-.24x=-8.16
x=-8.16/-.24
x=34 ounces of the 20% SOLUTION IS USED.
51-34=17 OUNCES OF THE 44% SOLUTION IS USED.
PROOF:
.20*34=.44*17=.28851
86.8+7.48=14.28
14.28=14.2