SOLUTION: Can you help me to solve this difficult equation.
In 1990, the St. Louis metropolitan area had an average of 82 x 10⁻⁶ g/m³ of pollutants in the air.
How many gram
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-> SOLUTION: Can you help me to solve this difficult equation.
In 1990, the St. Louis metropolitan area had an average of 82 x 10⁻⁶ g/m³ of pollutants in the air.
How many gram
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Question 864071: Can you help me to solve this difficult equation.
In 1990, the St. Louis metropolitan area had an average of 82 x 10⁻⁶ g/m³ of pollutants in the air.
How many grams of pollutants were there in 2 x 10³ m³ of air? Answer by josgarithmetic(39620) (Show Source):
You can put this solution on YOUR website! The first number is a concentration in mass per volume. The second number is a volume. This case fits . The question asks for how much mass of a dissolved or dispersed material.
g means grams as is a measure of mass.
m³ means cubic meters and is a unit of volume.
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