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| Question 863843:  Find the quadratic function that fits the data points for(-1,0) (3,0) (5,3)
 Answer by stanbon(75887)
      (Show Source): 
You can put this solution on YOUR website! Find the quadratic function that fits the data points for(-1,0) (3,0) (5,3) ------------------------
 Form::
 ax^2 + bx + c = y
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 Using (-1,0) you get a - b + c = 0
 Using (3,0) you get 9a + 3b + c = 0
 Using (5,3) you get 25a + 5a + c = 3
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 Use any method you know to solve the system:
 a = 1/4
 b = -1/2
 c = -3/4
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 Equation:
 y = (1/4)x^2 -(1/2)x -(3/4)
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 Cheers,
 Stan H.
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