SOLUTION: the length of a rectangle is 4 feet more than the width. the area of the rectangle is 32 square feet. find the length and width. round your answer to the nearest tenth of a foot

Algebra ->  Customizable Word Problem Solvers  -> Evaluation -> SOLUTION: the length of a rectangle is 4 feet more than the width. the area of the rectangle is 32 square feet. find the length and width. round your answer to the nearest tenth of a foot      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 863837: the length of a rectangle is 4 feet more than the width. the area of the rectangle is 32 square feet. find the length and width. round your answer to the nearest tenth of a foot
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!

Hi
A = Lw = (w+4)w = 32 ft^2
w^2 + 4w -32 = 0
(w + 8)(w-4) = 0 (Tossing out the negative solution for unit measure)
w = 4ft and L = 8ft