SOLUTION: 2/sqrt[3] + sqrt[2]
Can you help me rationalize the denominator? I really apprecuate your help. It would help so much if you could show me how you do this.
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-> SOLUTION: 2/sqrt[3] + sqrt[2]
Can you help me rationalize the denominator? I really apprecuate your help. It would help so much if you could show me how you do this.
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Question 86383This question is from textbook Intermediate Algebra
: 2/sqrt[3] + sqrt[2]
Can you help me rationalize the denominator? I really apprecuate your help. It would help so much if you could show me how you do this. This question is from textbook Intermediate Algebra
You can put this solution on YOUR website! 2/sqrt[3] + sqrt[2]
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Multiply numerator and denominator by (sqrt3 - sqrt2) to get:
[2(sqrt3 - sqrt2)]/[3-2]
=2(sqrt3 - sqrt2)
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Why does this work?
Because (sqrt3+sqrt2)(sqrt3-sqrt2) = 3+sqrt6-sqrt6-2 = 3-2=1
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Cheers,
Stan H.
Can you help me rationalize the denominator? I really apprecuate your help. It
would help so much if you could show me how you do this.
Form the conjugate surd of the denominator:
1. Copy the first term
2. Copy the second term with the sign changed.
The conjugate surd of the denominator is
. Write it over itself to form a
fraction equal to 1:
Multiply the original eqpression by that fraction. It doesn't
change the value because the fraction equals 1.
×
FOIL out the denominator:
Cancel the terms in in the bottom
You can multiply that out if you like and get
Edwin