SOLUTION: I have a question that states: graph: f(x)=-41/(x^2-36). How do I set this up and what does the graph look like?

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Question 86381: I have a question that states: graph: f(x)=-41/(x^2-36). How do I set this up and what does the graph look like?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
graph: f(x)=-41/(x^2-36).
You have vertical asymptotes at x=6 and at x=-6
As x goes to +infinity, y goes to -infinity
As x goes to -infinity, y goes to -infinity
You have no x-intercepts
The y-intercept is at -41/-36
Plot a few more points and you should be able to sketch the graph.
It looks like the following:
graph%28400%2C300%2C-10%2C10%2C-10%2C10%2C-41%2F%28x%5E2-36%29%29
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Cheers,
Stan H.