SOLUTION: for the equation y-3=3(x+1), what point does the line pass thru? i think it is (-1,3)--also for the same equation , what is the x intercept of the perpendicular line? i came up w

Algebra ->  Graphs -> SOLUTION: for the equation y-3=3(x+1), what point does the line pass thru? i think it is (-1,3)--also for the same equation , what is the x intercept of the perpendicular line? i came up w      Log On


   



Question 863737: for the equation y-3=3(x+1), what point does the line pass thru? i think it is (-1,3)--also for the same equation , what is the x intercept of the perpendicular line? i came up with x=5. can you check to see if i got them right or where i got off track?
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
A line passes through infinite set of points. Your equation is in point-slope form, and it is based on a particular point, (-1,3).
Arrange the equation into slope-intercept form and you can directly read the y intercept but you wanted the x intercept of a perpendicular line. This is ambiguous unless you have more information.

Your current equation is y=3x%2B3%2B3
y=3x%2B6.
The line perpendicular to it is y=-%281%2F3%29x%2Bb, and you do not have enough information described for determining b. The y-intercept is (0,b) for this perpendicular line.
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From y=-%281%2F3%29x%2Bb,
%281%2F3%29x%2By=b
x%2B3y=3b, which is STANDARD FORM, and you can "find" the x-intercept if set y=0 and solve for x, which gives you x=3b; but as stated, you need more information.