SOLUTION: The perimeter of a rectangle is 54 cm. It's length is 6 cm. What is it's width. solve algebraically and arithmetically. p = 2(l + w) 54 = 2(6 + w) 54 = 12 +2 w -12 -12 42

Algebra ->  Rectangles -> SOLUTION: The perimeter of a rectangle is 54 cm. It's length is 6 cm. What is it's width. solve algebraically and arithmetically. p = 2(l + w) 54 = 2(6 + w) 54 = 12 +2 w -12 -12 42       Log On


   

Question 863498: The perimeter of a rectangle is 54 cm. It's length is 6 cm. What is it's width. solve algebraically and arithmetically.
p = 2(l + w)
54 = 2(6 + w)
54 = 12 +2 w
-12 -12
42 = 2w
w = 21
second problem Jerry is 50 inches tall and is growing at the rate of 1/24 inch per month. Adam is 47 inches tall and is growing at the rate of 1/8 inch per month. If they continue to grow at the same rates for the next 4 years, in how many months will they be the same height?
solve 2 different ways
specify what basic mathematics concept/relation is used to support your solution

Answer by josgarithmetic(39621) About Me  (Show Source):
You can put this solution on YOUR website!
Helping just with your second question.

x is for months, and y is for how tall.
This is a simple two dimensional linear system problem.
Jerry starts at 50 inches and Adam at 47 inches in tallness.
Jerry's slope or growth rate is %281%2F24%29 inches per month and Adam's is %281%2F8%29 inche per month.

Their tallness equations are:
Jerry: highlight%28y=%281%2F24%29x%2B50%29
Adam: highlight%28y=%281%2F8%29x%2B47%29

You want to know the point of intersection for these two equations.
Find this intersection point, either algebraically or graphically.