SOLUTION: Find all values of x in the interval [0, 2π] that satisfy the given equation. (Enter your answers as a comma-separated list.) − sin 2x = sqrt(2)sin(x)

Algebra ->  Trigonometry-basics -> SOLUTION: Find all values of x in the interval [0, 2π] that satisfy the given equation. (Enter your answers as a comma-separated list.) − sin 2x = sqrt(2)sin(x)      Log On


   

Question 863144: Find all values of x in the interval [0, 2π] that satisfy the given equation. (Enter your answers as a comma-separated list.)
− sin 2x = sqrt(2)sin(x)
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Find all values of x in the interval [0, 2π] that satisfy the given equation. (Enter your answers as a comma-separated list.)
− sin 2x = sqrt(2)sin(x)
-2sixcosx=√2sinx
divide both sides by sinx
-2cosx=√2
cosx=-√2/2
x=3π/4, 5π/4 (in quadrants II and III in which cos<0)