SOLUTION: the length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle.
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Question 86312: the length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! the length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle.
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Let the width be "x" cm; length = "2x+2" cm.
Perimeter = 2(length + width)
52 = 2(2x+2+x)
26 = 3x+2
3x = 24
x = 8 cm (width)
x+2 = 10 cm (length)
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Cheers,
Stan H.
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