SOLUTION: Hi! Can you please help me with this problem? It's pretty simple, from what I can tell, but I just can't get my head around it - I'm stuck, unfortunately. I need to work out th

Click here to see ALL problems on Triangles

Question 863029: Hi! Can you please help me with this problem?
It's pretty simple, from what I can tell, but I just can't get my head around it - I'm stuck, unfortunately.
I need to work out the areas of a couple right-angled triangle. I know I need to use this formula: 1/2 x base x height. So, using that, how can I work out the area of triangle AEF (base = √5 + 3, height = 1) and triangle CDE (base = √5 + 1, height = √5 + 1/2).
I hope you don't mind that I've added two problems!
Thank you so much for your help in advanced! :)
Answer by rothauserc(4718) (Show Source):
You can put this solution on YOUR website!
1) Area(AEF) = (1/2)(square root(5) +3)*1 = (1/2)*(2.24+3) = 2.62
2) Area(CDE) = (1/2)(square root(5) +1)*(square root(5)+(1/2)) = (1/2)*(3.24)*(2.74) = 4.44