SOLUTION: A student drove a distance of 125 miles at an average speed of 55 mph. How much faster would she have to drive on the return trip to save 30 minutes of driving time?
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Question 862927: A student drove a distance of 125 miles at an average speed of 55 mph. How much faster would she have to drive on the return trip to save 30 minutes of driving time? Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! A student drove a distance of 125 miles at an average speed of 55 mph. How much faster would she have to drive on the return trip to save 30 minutes of driving time?
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let x=speed on the return trip to save 30 minutes of driving time
travel time=distance/speed
LCD:55x
125x-55*125=55x/2
250x-13750=55x
195x=13750
x=70.51
speed on the return trip to save 30 minutes of driving time=70.51 mph
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