SOLUTION: .A father is twice as old as his son. 20 years ago, the age of the father was 12 times the age of the son. The present age of the father (in years) is .Ten years ago, Kumar wa

Algebra ->  Test -> SOLUTION: .A father is twice as old as his son. 20 years ago, the age of the father was 12 times the age of the son. The present age of the father (in years) is .Ten years ago, Kumar wa      Log On


   

Question 862919: .A father is twice as old as his son. 20 years ago, the age of the father was 12 times the age of the son. The present age of the father (in years) is

.Ten years ago, Kumar was thrice as old as Selva was but 10 years hence, he will be only twice as old. Find Kumar’s present age.
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
x = age of father
y = age of son

Today: x=2y

Twenty Years Ago: %28x-20%29=12%28y-20%29

2y-20=12%28y-20%29
2y-20=12y-240
2y-12y=-240%2B20
-10y=-220
highlight%28y=22%29