SOLUTION: I need help with this problem: What is the standard form of an equation form of that passes through (3,0)and (6,-8).

Algebra ->  Linear-equations -> SOLUTION: I need help with this problem: What is the standard form of an equation form of that passes through (3,0)and (6,-8).      Log On


   

Question 86289: I need help with this problem: What is the standard form of an equation form of that passes through (3,0)and (6,-8).
Found 2 solutions by scianci, Edwin McCravy:
Answer by scianci(186) About Me  (Show Source):
You can put this solution on YOUR website!
Determine the slope:
%280+-+%28-8%29%29%2F%283+-+6%29 = 8%2F-3 = -8%2F3
The standard form is 8x + 3y = C [take the slope and change the sign]
Plug in the given coordinates (0 , -8) to find the appropriate value of C:
8(0) + 3(-8) = C
-24 = C
Equation is 8x + 3y = -24

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
I need help with this problem: What is the standard form of an equation form of that passes through (3,0)and (6,-8).


Use the slope formula:

    y2 - y1
m = —————————
    x2 - x1

where (x1, y1) = (3, 0) and (x2, y2) = (6,-8)

     (-8) - (0)     -8     
m = ———————————— = ———— = -8%2F3
      (6) - (3)      3     

Now substitute in the point slope formula:

  y - y1 = m(x - x1)

  y - 0 = -8%2F3(x - 3)

      y = -8%2F3(x - 3)

To clear of fractions, multiply both sides by LCD = 3

     3y = 3%28-8%2F3%29(x - 3)

Cancel the 3's just after the equal sign:

     3y = -8(x - 3)

     3y = -8x + 24

8x + 3y = 24 

Here's the graph:



Edwin