SOLUTION: y varies directly as x and inversely as the square of z.
Y=24 when X=12 and z=2. Find y when x=64 and z=4
y=
Only question on my homework i can't figure out! Thank you!
Algebra ->
Sequences-and-series
-> SOLUTION: y varies directly as x and inversely as the square of z.
Y=24 when X=12 and z=2. Find y when x=64 and z=4
y=
Only question on my homework i can't figure out! Thank you!
Log On
Question 862868: y varies directly as x and inversely as the square of z.
Y=24 when X=12 and z=2. Find y when x=64 and z=4
y=
Only question on my homework i can't figure out! Thank you! Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! y varies directly as x and inversely as the square of z.
--> y = k*x/z^2
---
Y=24 when X=12 and z=2. Find y when x=64 and z=4
Find k
24 = k*12/4
k = 8
----
y = k*x/z^2
y = 8*64/16
y = 32
=====================
It's not necessary to solve for k, but it simplifies it.
