SOLUTION: I am trying to solve in the simplest form {{{(y-2)/(y+3)}}} - {{{y/(2y+6)}}} I am getting {{{(y-2)/(y+3)}}} is this correct I am not sure and I really need the help

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: I am trying to solve in the simplest form {{{(y-2)/(y+3)}}} - {{{y/(2y+6)}}} I am getting {{{(y-2)/(y+3)}}} is this correct I am not sure and I really need the help      Log On


   

Question 86286This question is from textbook algebra
: I am trying to solve in the simplest form
%28y-2%29%2F%28y%2B3%29 - y%2F%282y%2B6%29
I am getting %28y-2%29%2F%28y%2B3%29 is this correct I am not sure and I really need the help This question is from textbook algebra

Answer by scianci(186) About Me  (Show Source):
You can put this solution on YOUR website!
%28y-2%29%2F%28y%2B3%29 - y%2F%282y%2B6%29
Determine the LCD of y + 3 and 2y + 6. Put the 2y + 6 in factored form:
%28y-2%29%2F%28y%2B3%29 - y%2F%282%28y%2B3%29%29
The LCD is 2(y + 3)
Change each fraction to an equivalent fraction having a denominator of 2(y + 3):
2%28y+-+2%29%2F%282%28y+%2B+3%29%29 - y%2F%282%28y%2B3%29%29
Distribute:
%282y+-+4%29%2F%282%28y+%2B+3%29%29 - y%2F%282%28y%2B3%29%29
Combine the numerators:
%282y+-+4%29%2F%282%28y+%2B+3%29%29 - y%2F%282%28y%2B3%29%29 =
%28y+-+4%29%2F%282%28y+%2B+3%29%29