SOLUTION: Solve for p a) (7p)^(-1) + (2p)^(-2) - 4 = 0 Can you please help me out? Thanks so much in advance:)

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Solve for p a) (7p)^(-1) + (2p)^(-2) - 4 = 0 Can you please help me out? Thanks so much in advance:)      Log On


   

Question 862852: Solve for p
a) (7p)^(-1) + (2p)^(-2) - 4 = 0
Can you please help me out? Thanks so much in advance:)
Answer by josgarithmetic(39625) About Me  (Show Source):
You can put this solution on YOUR website!
Easier to handle in positive exponents.
1%2F%287p%29%2B1%2F%284p%5E2%29-4=0
Simplest common denominator is 28p%5E2.
28p%5E2%281%2F%287p%29%2B1%2F%284p%5E2%29-4%29=0%2A28p%5E2
4p%2B7-4%2A28p%5E2=0
-112p%5E2%2B4p%2B7=0
highlight_green%28112p%5E2-4p-7=0%29

Now what? Use general solution for a quadratic equation to solve for p; but be sure to check each result in the original equation in case of one solution being false for the original equation.