SOLUTION: A box contains 9 balls, each a different color. In how many ways can a set of 3 balls be made, if the order in which they are chosen does not matter? Thank you for your help!

Algebra ->  Probability-and-statistics -> SOLUTION: A box contains 9 balls, each a different color. In how many ways can a set of 3 balls be made, if the order in which they are chosen does not matter? Thank you for your help!      Log On


   

Question 862741: A box contains 9 balls, each a different color. In how many ways can a set of 3 balls be made, if the order in which they are chosen does not matter?
Thank you for your help!
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
There are 9*8*7 = 504 ways to do this if order mattered.


Since order does not matter you have to divide by 3! = 3*2*1 = 6 to get 504/6 = 84. Note: there are 3! = 6 ways to order the 3 balls chosen


So the final answer is 84