SOLUTION: for the equation y-3=3(x+1), i think that the x intercept is 1 and if i write the equation in standard form it looks like this -3x+y=6. Does this look right?

Algebra ->  Graphs -> SOLUTION: for the equation y-3=3(x+1), i think that the x intercept is 1 and if i write the equation in standard form it looks like this -3x+y=6. Does this look right?      Log On


   



Question 862619: for the equation y-3=3(x+1), i think that the x intercept is 1 and if i write the equation in standard form it looks like this -3x+y=6. Does this look right?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
y-3=3(x+1)
Conert to slope-intercept form, y=mx%2Bb
y-3=3x%2B3
y=3x%2B6
The y-intercept is b=6
You forgot to multiply by the 3 in front of the parentheses.
.
.
.
Then convert to standard form, ax%2Bby=c
-3x%2By=6
3x-y=-6
Typically in standard form, the coefficient of x is positive.