SOLUTION: What proportion of members spend less than 40 minutes at the gym?given a mean of 80 minutes and standard deviation of 20

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Question 862576: What proportion of members spend less than 40 minutes at the gym?given a mean of 80 minutes and standard deviation of 20
Answer by ewatrrr(24785) About Me  (Show Source):
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Hi

mean of 80 minutes and standard deviation of 20

P( x< 40) = P(z < (40-80)/20 ) = P(z < -2)   invNorm(-2) = .0228  0r 2.28%