SOLUTION: A person rowed her boat upstream for a distance of 32 miles and then rowed backed to the starting point. The total time of the trip was 18 hours. If the rate of the current was 7

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Question 862389: A person rowed her boat upstream for a distance of 32 miles and then rowed backed to the starting point. The total time of the trip was 18 hours. If the rate of the current was 7 mph, find the average of the boat in still water.
My daughter and I are stuck on this problem, many thanks.

Found 3 solutions by Alan3354, josmiceli, richwmiller:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
A person rowed her boat upstream for a distance of 32 mil and then rowed backed to the starting point. The total time of the trip was 18 hours. If the rate of the current was 7 mph, find the average of the boat in still water.
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d = distance one way
c = speed of the current = 7
b = boat's speed
----
d = r*t
t = d/r
18 = 32/(b-7) + 32/(b+7)
18*(b-7)*(b+7) = 32*(b+7) + 32*(b-7)
9*(b^2 - 49) = 32b
9b%5E2+-+32b+-+49+=+0
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 9x%5E2%2B-32x%2B-49+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-32%29%5E2-4%2A9%2A-49=2788.

Discriminant d=2788 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28--32%2B-sqrt%28+2788+%29%29%2F2%5Ca.

x%5B1%5D+=+%28-%28-32%29%2Bsqrt%28+2788+%29%29%2F2%5C9+=+4.71119528498757
x%5B2%5D+=+%28-%28-32%29-sqrt%28+2788+%29%29%2F2%5C9+=+-1.15563972943202

Quadratic expression 9x%5E2%2B-32x%2B-49 can be factored:
9x%5E2%2B-32x%2B-49+=+%28x-4.71119528498757%29%2A%28x--1.15563972943202%29
Again, the answer is: 4.71119528498757, -1.15563972943202. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+9%2Ax%5E2%2B-32%2Ax%2B-49+%29

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b =~ 4.7112 mi/hr
------------------------------
It's not a simple problem.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +t+ = the time in hours to row upstream
+18+-+t+ = the time in hours to row downstream
Let +s+ = the rate of the boat in still water in mi/hr
------------------------------------------------
Rowing upstream:
(1) +32+=+%28+s+-+7+%29%2At+
Rowing downstream:
(2) +32+=+%28+s+%2B+7+%29%2A%28+18+-+t+%29+
----------------------------
(1) +t+=+32+%2F+%28+s-7+%29+
and
(2) +32+=+18s+%2B+126+-+st+-+7t+
(2) +t%2A%28+s+%2B+7+%29+-+18s+=+94+
(2) +t+=+%28+18s+-+94+%29+%2F+%28+s+%2B+7+%29+
(2) +32+%2F+%28+s+-+7+%29+=+%28+18s+-+94+%29+%2F+%28+s+%2B+7+%29+
(2) +32%2A%28+s+%2B+7+%29+=+%28+18s+-+94+%29%2A%28+s+-+7+%29+
(2) +32s+%2B+224+=+18s%5E2+-+94s+-+126s+%2B+658+
(2) +18s%5E2+-+252s+%2B+434+=+0+
(2) +9s%5E2+-+126s+%2B+217+=+0+
Use the quadratic formula to solve, then
find +t+
Check my math,I could have made an error
The method should be OK




Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
Both of the other tutors started out fine but made errors.
There is a simple answer.
What grade is your daughter in?
18 = (64 b)/((b-7) (b+7))
b=9
the boat goes 9 mph
One started out fine but made some simple errors
18 = (64 b)/(b^2-49)
18(b^2-49)-64b=0
18b^2-64b-49*18=0
18b^2-64b-882=0
using the quadratic equation
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 18x%5E2%2B-64x%2B-882+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-64%29%5E2-4%2A18%2A-882=67600.

Discriminant d=67600 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28--64%2B-sqrt%28+67600+%29%29%2F2%5Ca.

x%5B1%5D+=+%28-%28-64%29%2Bsqrt%28+67600+%29%29%2F2%5C18+=+9
x%5B2%5D+=+%28-%28-64%29-sqrt%28+67600+%29%29%2F2%5C18+=+-5.44444444444444

Quadratic expression 18x%5E2%2B-64x%2B-882 can be factored:
18x%5E2%2B-64x%2B-882+=+18%28x-9%29%2A%28x--5.44444444444444%29
Again, the answer is: 9, -5.44444444444444. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+18%2Ax%5E2%2B-64%2Ax%2B-882+%29


and factoring
Solved by pluggable solver: Factoring using the AC method (Factor by Grouping)


18%2Ax%5E2-64%2Ax-882 Start with the given expression.



2%289x%5E2-32x-441%29 Factor out the GCF 2.



Now let's try to factor the inner expression 9x%5E2-32x-441



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Looking at the expression 9x%5E2-32x-441, we can see that the first coefficient is 9, the second coefficient is -32, and the last term is -441.



Now multiply the first coefficient 9 by the last term -441 to get %289%29%28-441%29=-3969.



Now the question is: what two whole numbers multiply to -3969 (the previous product) and add to the second coefficient -32?



To find these two numbers, we need to list all of the factors of -3969 (the previous product).



Factors of -3969:

1,3,7,9,21,27,49,63,81,147,189,441,567,1323,3969

-1,-3,-7,-9,-21,-27,-49,-63,-81,-147,-189,-441,-567,-1323,-3969



Note: list the negative of each factor. This will allow us to find all possible combinations.



These factors pair up and multiply to -3969.

1*(-3969) = -3969
3*(-1323) = -3969
7*(-567) = -3969
9*(-441) = -3969
21*(-189) = -3969
27*(-147) = -3969
49*(-81) = -3969
63*(-63) = -3969
(-1)*(3969) = -3969
(-3)*(1323) = -3969
(-7)*(567) = -3969
(-9)*(441) = -3969
(-21)*(189) = -3969
(-27)*(147) = -3969
(-49)*(81) = -3969
(-63)*(63) = -3969


Now let's add up each pair of factors to see if one pair adds to the middle coefficient -32:



First NumberSecond NumberSum
1-39691+(-3969)=-3968
3-13233+(-1323)=-1320
7-5677+(-567)=-560
9-4419+(-441)=-432
21-18921+(-189)=-168
27-14727+(-147)=-120
49-8149+(-81)=-32
63-6363+(-63)=0
-13969-1+3969=3968
-31323-3+1323=1320
-7567-7+567=560
-9441-9+441=432
-21189-21+189=168
-27147-27+147=120
-4981-49+81=32
-6363-63+63=0




From the table, we can see that the two numbers 49 and -81 add to -32 (the middle coefficient).



So the two numbers 49 and -81 both multiply to -3969 and add to -32



Now replace the middle term -32x with 49x-81x. Remember, 49 and -81 add to -32. So this shows us that 49x-81x=-32x.



9x%5E2%2Bhighlight%2849x-81x%29-441 Replace the second term -32x with 49x-81x.



%289x%5E2%2B49x%29%2B%28-81x-441%29 Group the terms into two pairs.



x%289x%2B49%29%2B%28-81x-441%29 Factor out the GCF x from the first group.



x%289x%2B49%29-9%289x%2B49%29 Factor out 9 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.



%28x-9%29%289x%2B49%29 Combine like terms. Or factor out the common term 9x%2B49



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So 2%289x%5E2-32x-441%29 then factors further to 2%28x-9%29%289x%2B49%29



===============================================================



Answer:



So 18%2Ax%5E2-64%2Ax-882 completely factors to 2%28x-9%29%289x%2B49%29.



In other words, 18%2Ax%5E2-64%2Ax-882=2%28x-9%29%289x%2B49%29.



Note: you can check the answer by expanding 2%28x-9%29%289x%2B49%29 to get 18%2Ax%5E2-64%2Ax-882 or by graphing the original expression and the answer (the two graphs should be identical).