SOLUTION: What is the equation of a circle with center (0, 3) and radius 3?

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: What is the equation of a circle with center (0, 3) and radius 3?      Log On


   

Question 86233: What is the equation of a circle with center (0, 3) and radius 3?
Answer by dolly(163) About Me  (Show Source):
You can put this solution on YOUR website!
Center is (0,3) and radius is 3.
So equation of the circle is (x-0)^2 + (y-3)^2 = 3^2
==> x^2 + (y-3)^2 = 9
On further simplification,
==> x^2 + y^2 - 6y + 9 = 9
or x^2 + y^2 - 6y = 0