SOLUTION: Logx+log(x+3)=log10
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Question 862159
:
Logx+log(x+3)=log10
Answer by
lwsshak3(11628)
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Logx+log(x+3)=log10
solve for x:
log(x*(x+3))=log10
x^2+3x=10
x^2+3x-10=0
(x+5)(x-2)=0
x=-5(reject, x>0)
or
x=2