SOLUTION: A and B play 12 games of chess of which 6 are won by A, 4 are won by B, 2 ends in a draw. They agree to play a tournament consisting of 3 games. Find the probability that (a) A win

Algebra ->  Probability-and-statistics -> SOLUTION: A and B play 12 games of chess of which 6 are won by A, 4 are won by B, 2 ends in a draw. They agree to play a tournament consisting of 3 games. Find the probability that (a) A win      Log On


   

Question 862124: A and B play 12 games of chess of which 6 are won by A, 4 are won by B, 2 ends in a draw. They agree to play a tournament consisting of 3 games. Find the probability that (a) A wins all 3 games (b) two games end in a draw, (c) A and B win alternatively, (d) B wins atleast one games.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Look at all the possible outcomes there are 3^3 or 27 of them.
AAA AAB AAD ABA ABB ABD ADA ADB ADD
BAA BAB BAD BBA BBB BBD BDA BDB BDD
DAA DAB DAD DBA DBB DBD DDA DDB DDD
A) P%28AAA%29=1%2F27
B) P%282D%29=5%2F27+
C) I assume that mean BAB ABD etc.,There are six of those (BAB,DAB,BAD,ABA,DBA,ABD) P=6%2F27=2%2F9
D) P%281B%29=19%2F27