SOLUTION: Part1: The graph of is x2/169-y2/16=1 a hyperbola centered at the orgin. what are the value of a and b? What are the slopes of the asymptotes for the hyperbola in part 1? Show

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Part1: The graph of is x2/169-y2/16=1 a hyperbola centered at the orgin. what are the value of a and b? What are the slopes of the asymptotes for the hyperbola in part 1? Show      Log On


   

Question 861944: Part1: The graph of is x2/169-y2/16=1 a hyperbola centered at the orgin. what are the value of a and b?

What are the slopes of the asymptotes for the hyperbola in part 1? Show your work.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

x2%2F169-y2%2F16=1+

x2%2F13%5E2-y2%2F4%5E2=1+

  a = 13  and b = 4  slopes  m =  ± 4/13

Standard Form of an Equation of an Hyperbola opening right and  left is:

  %28x-h%29%5E2%2Fa%5E2+-+%28y-k%29%5E2%2Fb%5E2+=+1 with C(h,k) and vertices 'a' units right and left of center,   2a the length of the transverse axis

Foci are sqrt%28a%5E2%2Bb%5E2%29 units right and left of center along y = k

& Asymptotes Lines passing thru C(h,k), with slopes  m =  ± b/a