SOLUTION: Question: 9^2x *27^x^2=3^-1, I am trying to find x. I tried to change base 9 to base 3 and multiplied the exponent by 2 and I got 4x then I changed base 27 to base 3 and multipl

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Question: 9^2x *27^x^2=3^-1, I am trying to find x. I tried to change base 9 to base 3 and multiplied the exponent by 2 and I got 4x then I changed base 27 to base 3 and multipl      Log On


   

Question 861695: Question: 9^2x *27^x^2=3^-1, I am trying to find x.
I tried to change base 9 to base 3 and multiplied the exponent by 2 and I got 4x then I changed base 27 to base 3 and multiplied the exponent by 3 but I'm not sure if I'm correct so far.

Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
9^2x *27^x^2=3^-1
3^(6x)*3^(3x)=3^(-1)
3^(9x) = 3^(-1)
9x=-1
x=-1/9