SOLUTION: a radiator contains 6 L of a 44% antifreeze mixture. how much pure antifreeze should be added to make a mixture that is 52% antifreeze.

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Question 861676: a radiator contains 6 L of a 44% antifreeze mixture. how much pure antifreeze should be added to make a mixture that is 52% antifreeze.
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
.44*6+x=.52*(6+x)
x=1