SOLUTION: Sohrab is taking a long walk. He always finds it interesting to see how many sidewalk cracks he stepped on. The cracks are 5 1/4 feet apart. The cracks are very thin. His stride is

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: Sohrab is taking a long walk. He always finds it interesting to see how many sidewalk cracks he stepped on. The cracks are 5 1/4 feet apart. The cracks are very thin. His stride is      Log On

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Question 861512: Sohrab is taking a long walk. He always finds it interesting to see how many sidewalk cracks he stepped on. The cracks are 5 1/4 feet apart. The cracks are very thin. His stride is 2 3/4 feet long (measured from heel to heel). Assume his foot has to overlap a crack by at least an inch for him to count it. If he starts his walk with both heels just barely past a crack, what fraction of the cracks will he step on during his walk? (Beginning of the cycle starts when his heel is just past a crack. Cycle is the number of cracks. Only count the beginning or end crack, not both, just count one of them.)The fraction of the cracks he steps on is the number of cracks he steps on divided by the number of cracks in the cycle.
I am confused on how to solve this problem, and need help getting the answer. I assume the cycle starts at the first crack where his heels start, and I think that converting the fractions to the same denominator would help but I am not sure how to calculate the size of his foot and his pace?

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
I assume the cycle starts at the first crack where his heels start.
No, it states" If he starts his walk with both heels just barely past a crack,"
Use decimals
5.25 =5 1/4 or 21 /4
2.75=2 3/4 or 11/4
Good point about not knowing the size of his foot but his pace or stride is 2 3/4 feet long