SOLUTION: write an equation in standard form of the line that passes through the point P(6,-1) and is perpendicular to the line described by the equation -2x + 3y = -6

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Question 861427: write an equation in standard form of the line that passes through the point P(6,-1) and is perpendicular to the line described by the equation -2x + 3y = -6
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
This is how standard form equation for a line works:
ax%2Bby=c, standard form.
Solve for y.
by=-ax%2Bc
y=-%28a%2Fb%29x%2Bc%2Fb, slope-intercept form.

The slope is -%28a%2Fb%29 and the y-intercept is c%2Fb.

What you should know about perpendicular lines:
If two lines are perpendicular and their slopes are m%5B1%5D and m%5B2%5D, then m%5B1%5D%2Am%5B2%5D=-1.

Returning to you given equation and to find line perpendicular containing P(6,-1):
The line perpendicular to the given -2x%2B3y=-6 is highlight_green%283x%2B2y=c%29, and knowing that this new line must contain the point (6,-1), use those coordinates to compute c.
highlight_green%28c=3%2A6%2B2%28-1%29%29.