SOLUTION: How do you find radian measures of cot(theta)-6=2cot(theta)+2 between intervals 0<=theta<=2&#960;

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Question 861207: How do you find radian measures of cot(theta)-6=2cot(theta)+2 between intervals 0<=theta<=2π
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
How do you find radian measures of cot(theta)-6=2cot(theta)+2 between intervals 0<=theta<=2π
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use x for theta:
cot%28x%29-6=2cot%28x%29%2B2
cot%28x%29=-8
tan(x)=-1/cot(x)=-1/8
use inverse tan key on calculator set to radians.
x=3.0172, 6.1588 radians (In quadrants II and IV in which tan and cot<0)
note:(let me know if my solution is correct, helpful and understandable)