SOLUTION: Pls do help in solving my problem: Two parallel chords of length 10cm and 14cm lie on the same side of a circle of radius 24cm find the distance between the chords

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Question 861182: Pls do help in solving my problem:
Two parallel chords of length 10cm and 14cm lie on the same side of a circle of radius 24cm find the distance between the chords
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
Half of the longer chord measures 14cm%2F2=7cm.
Half of the shorter chord measures 10cm%2F25cm.
Drawing, not to scale:
The perpendicular bisector of a chord goes through the center of the circle.
Along with one half of the chord and the radius to one of the chord's ends, it forms a right triangle.
With the two chords, we have two right triangles.
In each of those triangles the hypotenuse measures 24 cm.
The legs of one of those triangles measure xcm and 7 cm,
so x%5E2%2B7%5E2=24%5E2 --> x%5E2%2B49=576 --> x%5E2=576-49 --> x%5E2=527 --> x=sqrt%28527%29=about22.96
The legs of the other triangle measure ycm and 5 cm,
so x%5E2%2B5%5E2=24%5E2 --> x%5E2%2B25=576 --> x%5E2=576-25 --> x%5E2=551 --> x=sqrt%28551%29=about23.47
The distance between the chords is
sqrt%28551%29-sqrt%28527%29= approx.23.47cm-22.96cm= approx.0.51cm