SOLUTION: Find a polar form of the equation x^2+y^2-8x=0

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Question 861117: Find a polar form of the equation x^2+y^2-8x=0
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find a polar form of the equation x^2+y^2-8x=0
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Conversion formulas:
x = rcos(t)
y = rsin(t)
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x^2 + y^2 - 8x = 0
(rcos(t))^2 + (rsin(t))^2 - 8rcos(t) = 0
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r^2(cos^2(t) + sin^2(t)) = 8rcos(t)
r^2 - 8rcos(t) = 0
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Cheers,
Stan H.
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