SOLUTION: consider a pack of 52 playing cards >4 suites-diamonds, hearts, spades ands clubs >Aces, kings, queens and jacks make picture cards. a)what is the probability that a card chos

Algebra ->  Probability-and-statistics -> SOLUTION: consider a pack of 52 playing cards >4 suites-diamonds, hearts, spades ands clubs >Aces, kings, queens and jacks make picture cards. a)what is the probability that a card chos      Log On


   

Question 860590: consider a pack of 52 playing cards
>4 suites-diamonds, hearts, spades ands clubs
>Aces, kings, queens and jacks make picture cards.
a)what is the probability that a card chosen at random
will be:
1)a picture card
2)an aces
3)ace of diamonds
4)a spade of a king
b)what is the probability that 2 cars are chosen
after the other, without replacement:
1)will both be diamonds
2)will both be picture cards
3)Will not be a picture card
4)will both be picture cards and clubs

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

Probability for ALL the following will be P = +highlight_green%28Type%2FTotal%29+  will let You reduce

1)a picture card  16%2F52

 2)an aces 4%2F52

 3)ace of diamonds 1%2F52

 4)a spade of a king 1%2F52

 

 b)what is the probability that 2 cards are chosen after the other, without replacement:

 1)will both be diamonds %2813%2F52%29%2812%2F51%29

 2)will both be picture cards %2816%2F52%29%2815%2F51%29

 3)Will not be a picture card %2836%2F52%29%2835%2F51%29

 4)will both be picture cards and clubs %284%2F52%29%283%2F51%29