SOLUTION: Find the vertices and foci of the hyperbola given by the equation x^2/25 - y^2/24 + 1

Algebra ->  Trigonometry-basics -> SOLUTION: Find the vertices and foci of the hyperbola given by the equation x^2/25 - y^2/24 + 1      Log On


   



Question 860407: Find the vertices and foci of the hyperbola given by the equation
x^2/25 - y^2/24 + 1

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
x^2/25 - y^2/24 = 1 C(0,0), Opening right and left along y = 0
Vertices (-5,0) and (5,0), foci (-7,0) and (7,0)
Note: |sqrt(25 + 24)| = 7
Standard Form of an Equation of an Hyperbola opening right and left is:
%28x-h%29%5E2%2Fa%5E2+-+%28y-k%29%5E2%2Fb%5E2+=+1 with C(h,k) and vertices 'a' units right and left of center, 2a the length of the transverse axis
Foci are sqrt%28a%5E2%2Bb%5E2%29 units right and left of center along y = k