SOLUTION: Please give explanation and steps for Find the vertices and asymptotes of the hyperbola given by the equation y^2/9 - x^2/16 = 1

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Question 860403: Please give explanation and steps for Find the vertices and asymptotes of the hyperbola given by the equation
y^2/9 - x^2/16 = 1

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
%28y%29%5E2%2Fhighlight_green%283%5E2%29+-+%28x-2%29%5E2%2F16+=+1 C(0,0) opening Up and down along x = 0
Vertices: V(0,-3) and V(0,3) highlight_green%283%29 units up and down from center
foci: F(0,-5) and F(0, 5) |sqrt%289%2B16%29| = 5 units up and down from center
Asymptotes: slopes m = ± 3/4, thru (0,0), y = ± (3/4)x
Standard Form of an Equation of an Hyperbola opening up and down is:
%28y-k%29%5E2%2Fb%5E2+-+%28x-h%29%5E2%2Fa%5E2+=+1 with C(h,k) and vertices 'b' units up and down from center, 2b the length of the transverse axis
Foci sqrt%28a%5E2%2Bb%5E2%29units units up and down from center, along x = h
& Asymptotes Lines passing thru C(h,k), with slopes m = ± b/a