SOLUTION: Please show the steps on how to solve: Find the vertex, focus, and directrix of the parabola given by the equation x^2 - 8x-16y+16 =0

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Question 860387: Please show the steps on how to solve:
Find the vertex, focus, and directrix of the parabola given by the equation x^2 - 8x-16y+16 =0
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

 x^2 - 8x-16y+16 =0

 x^2 - 8x = 16y-16 

(x-4)^2 = 16y - 16 + 16

 (x-4)^2 = 16y

  y = (1/16)(x-4)^2  V(4,0)  x = 4 line of symmetry

a+=+1%2F%284p%29+=+1%2F16, p = 4, focus(4,4), y = -4 directrix