SOLUTION: Find (x,y) position of centroid of the area under the curve y = 1(plus)x(plus)x^2 from x=0,x=2.

Algebra ->  Test -> SOLUTION: Find (x,y) position of centroid of the area under the curve y = 1(plus)x(plus)x^2 from x=0,x=2.      Log On


   

Question 860357: Find (x,y) position of centroid of the area under the curve y = 1(plus)x(plus)x^2 from x=0,x=2.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
First find the area.

Now,

x%5Bc%5D=10%2F%2826%2F3%29=%285%2A3%29%2F13=15%2F13
.
.
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y%5Bc%5D%2AA=%281%2F2%29%2832%2F5%2B8%2B8%2B4%2B2-%280%2B0%2B0%2B0%2B0%29%29=71%2F5
y%5Bc%5D=%2871%2F5%29%2F%2820%2F3%29=213%2F100