SOLUTION: 1+cscA=cscA(1+sinA) ~ How to prove that LS=RS
Algebra
->
Trigonometry-basics
-> SOLUTION: 1+cscA=cscA(1+sinA) ~ How to prove that LS=RS
Log On
Algebra: Trigonometry
Section
Solvers
Solvers
Lessons
Lessons
Answers archive
Answers
Click here to see ALL problems on Trigonometry-basics
Question 860074
:
1+cscA=cscA(1+sinA) ~ How to prove that LS=RS
Answer by
jim_thompson5910(35256)
(
Show Source
):
You can
put this solution on YOUR website!
I'm only going to be altering the right side.
1+cscA=cscA(1+sinA)
1+cscA=cscA(1)+cscA(sinA) ... distribution
1+cscA=cscA(1)+1/sinA(sinA) ... Substitution (note: csc(A) = 1/sin(A))
1+cscA=cscA+sinA/sinA ... multiplication
1+cscA=cscA+1 ... division
1+cscA=1+cscA ... use the commutative property of addition
So the identity is confirmed.