SOLUTION: 1+cscA=cscA(1+sinA) ~ How to prove that LS=RS

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Question 860074: 1+cscA=cscA(1+sinA) ~ How to prove that LS=RS
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
I'm only going to be altering the right side.


1+cscA=cscA(1+sinA)


1+cscA=cscA(1)+cscA(sinA) ... distribution


1+cscA=cscA(1)+1/sinA(sinA) ... Substitution (note: csc(A) = 1/sin(A))


1+cscA=cscA+sinA/sinA ... multiplication


1+cscA=cscA+1 ... division


1+cscA=1+cscA ... use the commutative property of addition


So the identity is confirmed.