Question 85999: Can you please help me with this probability question. It is from textbook Algebra II by A Beka Book. I tried to use the solution provided for question 83651 but couldn't solve it.
In a sample bag of M&M's candy, there are 5 brown, 6 yellow, 4 blue, 3 green, and 2 orange.
What is the probability of getting-
a)1 green M&M if only 1 is taken at a time?
b)3 yellow M&M's if 3 are taken at a time?
c)1 brown and 2 orange M&M's if 3 are taken at a time?
Thank you so much for your help!
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! In a sample bag of M&M's candy, there are 5 brown, 6 yellow, 4 blue, 3 green, and 2 orange.
What is the probability of getting-
a)1 green M&M if only 1 is taken at a time?
P(1 green) = 3/20
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b)3 yellow M&M's if 3 are taken at a time?
P(3 yellow) = 6C3/20C3 = [6*5*4/1*2*3]/[20*19*18/1*2*3]
=0.01754
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c)1 brown and 2 orange M&M's if 3 are taken at a time?
P(1 brown and 2 orange) = [P(1 brown) + P(2 orange)]/20C3
=[P(1 brown)*P(2 orange|1 brown)]/ 20C3
=[(5/20)*2C2/19C2]/20C3
=[(1/4)*(1/171)]/1140
=[0.001462]/1140
=0.00000128
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Cheers,
Stan H.
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