SOLUTION: the velocity of a dropped object when it hits the ground can be found using v= the square root of 2gd where v is the velocity in feet per second g is the acceleration due to gravit
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Question 859981: the velocity of a dropped object when it hits the ground can be found using v= the square root of 2gd where v is the velocity in feet per second g is the acceleration due to gravity and d is the distance in feet the object drops find the speed of a penny when it hits the ground after being dropped from 984 feet is 32 feet per second squared for g Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! the velocity of a dropped object when it hits the ground can be found using v= the square root of 2gd where v is the velocity in feet per second g is the acceleration due to gravity and d is the distance in feet the object drops find the speed of a penny when it hits the ground after being dropped from 984 feet is 32 feet per second squared for g
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v = the square root of 2gd
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v = sqrt(2gd)
Solve for "g"::
32 = sqrt(2*g*984)
1968g = 32^2
g = 0.5203 ft/sec^2 (acceleration due to gravity)
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Cheers,
Stan H.
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