SOLUTION: find the vertex, focus, and directrix of the parabola given by the equation x^2 - 8x - 16y + 16 = 0. The textbook does not explain this skill well, thank you for your help!
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-> SOLUTION: find the vertex, focus, and directrix of the parabola given by the equation x^2 - 8x - 16y + 16 = 0. The textbook does not explain this skill well, thank you for your help!
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Question 859895: find the vertex, focus, and directrix of the parabola given by the equation x^2 - 8x - 16y + 16 = 0. The textbook does not explain this skill well, thank you for your help! Answer by ewatrrr(24785) (Show Source):
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the vertex form of a Parabola opening up(a>0) or down(a<0),
where(h,k) is the vertex
x^2 - 8x - 16y + 16 = 0
(x-4)^2 - 16 -16y + 16 = 0 V = (4,0) x = 4 line of symmetry
a = 1/4p = 1/16, p = 4
focus is (h,k + p) (4,4)
With Directrix y = (k - p) y = -4
