SOLUTION: #1 A poker hand consisting of 6 cards is dealt from a standard deck of 52 cards. Find the probability that the hand contains exactly 5 face cards. Round your answer to 4 dec

Algebra ->  Probability-and-statistics -> SOLUTION: #1 A poker hand consisting of 6 cards is dealt from a standard deck of 52 cards. Find the probability that the hand contains exactly 5 face cards. Round your answer to 4 dec      Log On


   



Question 859866: #1

A poker hand consisting of 6 cards is dealt from a standard deck of 52 cards. Find the probability that the hand contains exactly 5 face cards.
Round your answer to 4 decimal places as needed.

#2

There are 17 female board members and 16 male board members. If a committee of 9 members is randomly chosen, what is the probability that the committee has exactly 5 females?
Round your answer to 6 decimal places as needed.

#3

If you randomly place your 8 books on the bookshelf, what is the probability that they will end up in alphabetical order?
Round your answer to 6 decimal places as needed.

#4

6 freshmen, 9 sophomores, 10 juniors, and 7 seniors are eligible to be on a committee. If a committee of 14 students is chosen at random, what is that probability that it is made up of 2 freshmen, 3 sophomores, 4 juniors, and 5 seniors?
Round your answer to 6 decimal places as needed.

#5

6 freshmen, 8 sophomores, 7 juniors, and 10 seniors are eligible to be on a committee. If a committee of 14 students is chosen at random, what is that probability that it is made up of 2 freshmen, 3 sophomores, 4 juniors, and 5 seniors?
Round your answer to 6 decimal places as needed
I need help by april 8th at 11:59pm and thanks

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
1)there are 12 face cards(K,Q and J in each of 4 suits) in Deck.
Choose 6(4 face and 2 others), p(4 face cards) = %2812C4%29%2840C2%29%2F%2852C6%29=495%2A780%2F%2820358520%29 = .0190
Saw another posted #860254, no work there as well
Whoa.. if You do not learn HOW to do these..this assignment is not going to
mean much. got You started with 'special ways'...check each out completely...
finding combinations, arithmetic etc
P = special ways/total ways
1)P = special ways/(52C6) = special ways/20,358,520 =%28%2812C5%29%2840C1%29%29%2F20358520= 72%2A40%2F%2820358520%29 = .000141
2)33 to chose 9 from
P = special ways/(33C9) = special ways/38567100 = %28%2817C5%29%2816C4%29%29%2F38567100+=+6188%2A1820%2F38567100 = .2920147
3) P = special ways/8! = 1%2F8%21 = .000025 (only 1 way books are alphabetical left to right)
4)32 to chose 14 from
P = special ways/(32C14)= special ways/471,435,600 = %28%286C2%29%289C3%29%2810C4%29%287%0D%0Ac5%29%29%2F471435600+
5) 31 to chose 14 from
P = special ways/(31C14) = special ways/265,182,525 =%28%286C2%29%288C3%29%287C4%29%2810%0D%0Ac5%29%29%2F265182525
You work on the number of Special ways for each