SOLUTION: Find all angles theta such that 0 < theta < 2pi and theta satisfies the following: 2sin^2(x)=1

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Question 859858: Find all angles theta such that 0 < theta < 2pi and theta satisfies the following:
2sin^2(x)=1
Found 2 solutions by stanbon, ewatrrr:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find all angles theta such that 0 < theta < 2pi and theta satisfies the following:
2sin^2(x)=1
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sin^2(x) = 1/2
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sin(x) = 1/sqrt(2) or sin(x) = -1/sqrt(2)
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x = pi/4 or (3/4)pi or (5/4)pi or (7/4)pi
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Cheers,
Stan H.
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Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

0+%3C+theta+%3C+2pi

2sin^2(x)=1

sin^2(x)=1/2

sin(x) = ± sqrt%281%2F2%29 = ± 1%2Fsqrt%282%29 = ± sqrt%282%29%2F2

Following (c0sx, sinx) unit circle summary for Your reference