SOLUTION: please,sir,help me urgently solve this question. the question is- 1cube = 1square 1cube + 2cube + 3cube= 9+27 = 36 =(1+2+3)whole square 1cube +

Algebra ->  Sequences-and-series -> SOLUTION: please,sir,help me urgently solve this question. the question is- 1cube = 1square 1cube + 2cube + 3cube= 9+27 = 36 =(1+2+3)whole square 1cube +      Log On


   

Question 85983: please,sir,help me urgently solve this question.
the question is- 1cube = 1square
1cube + 2cube + 3cube= 9+27 = 36 =(1+2+3)whole square
1cube + 2cube + 3cube + 4cube= 36+64=100=(1+2+3+4)whole square
use this pattern to find the sum of the cubes of the first ten natural numbers.
Answer by 303795(602) About Me  (Show Source):
You can put this solution on YOUR website!
1%5E3++=+%281%29%5E2
1%5E3+%2B+2%5E3+=+%281%2B2%29%5E2
1%5E3+%2B+2%5E3+%2B+3%5E3++=+%281%2B2%2B3%29%5E2
1%5E3+%2B+2%5E3+%2B+3%5E3+%2B+4%5E3+=+%281%2B2%2B3%2B4%29%5E2
Your pattern appears to be
The sum of n base numbers cubed = (sum the base numbers) then square the result.
This would give a result
sum of the cubes of the first ten natural numbers = %281%2B2%2B3%2B4%2B5%2B6%2B7%2B8%2B9%2B10%29%5E2=55%5E2
=3025